Self-ionisation of Water and Kw
HSC Chemistry Syllabus
- calculate and apply the dissociation constant (Ka) and pKa (pKa = –log10 (Ka)) to determine the difference between strong and weak acids (ACSCH098)
Self-ionisation of Water and KwKw Explained
What is Self-ionisation of Water?
Self-ionisation or auto-ionisation of water is a reversible reaction that occurs between two molecules of water. In this reaction, a proton is transferred from one water molecule to another, forming a hydroxide and hydronium ion.
2H2O(l)⇌H3O+(aq)+OH−(aq)2H2O(l)⇌H3O+(aq)+OH−(aq)
This reversible reaction occurs in pure water and all aqueous solutions e.g. acid or base solutions. In a closed chemical system, this reaction can reach an equilibrium.
The equilibrium constant of this reaction is represented by Kw=1.0×10-14Kw=1.0×10−14 at 25 ºC.
Kw=[H3O+][OH−]=1.0×10−14Kw=[H3O+][OH−]=1.0×10−14
This equation can be used to calculate the concentration of either ions in water or an aqueous solution when the concentration of the other is given.
Example 1
The hydrogen ion concentration of a hydrofluoric acid solution is 0.0700 mol/L at 25ºC. What is the hydroxide concentration?
Solution:
[H3O+][OH−]=1.0×10−14[H3O+][OH−]=1.0×10−14
[OH−]=1.0×10−140.0700[OH−]=1.0×10−140.0700
[OH−]=1.43×10−13 mol/L (3 s.f.)[OH−]=1.43×10−13 mol/L (3 s.f.)
Effect of Temperature on Water's Self-ionisation
The self-ionisation of water is an endothermic reaction (ΔH>0ΔH>0) as the energy absorbed during bond breaking is greater than the energy released during bond formation.
Since KwKw is an equilibrium constant, its value is affected by temperature.
- At a temperature > 25ºC, the equilibrium position shifts to the product side to produce more ions, thereby increasing the value of KwKw.
- At a temperature < 25ºC, the equilibrium position shifts to the reactant side, thereby reducing the equilibrium concentration of hydroxide and hydronium ions and decreasing the value of KwKw.
At 25ºC, the extremely small value of KwKw suggests that the equilibrium concentrations of H3O+H3O+ and OH-OH− ions are small. In pure water, the production of equal concentrations of these ions makes it neutral. When these ion concentrations change with temperature (as explained above), they remain equal and thus pure water remains neutral at all temperatures.
Relationship Between Kw, Ka and Kb
Self-ionisation of water does not only occur in pure water, it occurs in all aqueous solutions. For example, the above equilibrium can occur in a solution of acid or base.
This is what you need to remember and understand: KwKw is the product of KaKa of a weak acid and KbKb of its conjugate base.
Kw=Ka×KbKw=Ka×Kb
Derivation (do not memorise): For a generic acid-base system,
Acid:HA(aq)+H2O(l)⇋A−(aq)+H3O+(aq)Ka=[A−][H3O+][HA]Acid:HA(aq)+H2O(l)⇋A−(aq)+H3O+(aq)Ka=[A−][H3O+][HA]
Conjugate base:A−(aq)+H2O(l)⇋HA(aq)+OH−(aq)Kb=[HA][OH−][A−]Conjugate base:A−(aq)+H2O(l)⇋HA(aq)+OH−(aq)Kb=[HA][OH−][A−]
Let's multiply the expressions for KaKa and KbKb:
Ka×Kb=[A−][H3O+][HA]×[HA][OH−][A−]Ka×Kb=[A−][H3O+][HA]×[HA][OH−][A−]
Ka×Kb=[H3O+(aq)][OH−(aq)]=1.0×10−14Ka×Kb=[H3O+(aq)][OH−(aq)]=1.0×10−14
This means at 25℃ (298 K):
Ka=10−14KbKb=10−14KaKa=10−14KbKb=10−14Ka
These equations suggest that KaKa of a weak acid's ionisation is inversely proportional to the KbKb of its conjugate base's ionisation. The stronger an acid is, the weaker its conjugate base is; the weaker an acid is, the stronger its conjugate base is. This relationship is also true for a weak base and its conjugate acid.
Since these equilibrium constant values also indicate the strength of the acid and base respectively, we can formulate the following relationship:
|
Weak acid |
Conjugate weak base |
High Ka & low pKa |
High strength |
Low strength |
Low Ka & high pKa |
Low strength |
High strength |
|
Weak base |
Conjugate weak acid |
High Kb & low pKb |
High strength |
Low strength |
Low Kb & high pKb |
Low strength |
High strength |
Note the concept of pKapKa is discussed separately here